Question

A car covers a distance of 10
km along an inclined plane
under the action of a horizontal
force of 5 N. The work done on
car is 25kJ. The inclination of
the plane to horizontal is​

Answer 1

Explanation:

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Answer 2

Concept:

We need to apply the formula of work over here. Work = Force × displacement. Work = f cosθ × s

Given:

displacement = 10 km =  10 ×10³ m

Force, f = 5 N

Work done = 25 kJ = 25 ×10³ J

Find:

We need to determine the inclination of the plane to horizontal, θ.

Solution:

When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work in physics.

It is mathematically expressed by the formula, W = Fs where W = work done, F = Force and s = displacement

Cos theta, which is used to define work done, is the angle formed by the force applied and the displacement.

It is mathematically expressed as, W = Fcosθ×s ---- equation 1

We have been given that 5 N force is applied to bring about 25kJ = 25  ×10³ J of work with a displacement of s= 10 km = 10 ×10³m

Therefore, equation 1 becomes, W = Fcosθ×s

25 ×10³ = 5cosθ×10 ×10³

Therefore, 5cosθ = 25/10 = 25/50

Therefore, cosθ = 1/2

θ = cos^-1 (1/2)

θ = 60⁰

Thus, The inclination of the plane to horizontal is​ 60⁰.

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