Question

✍a car covers a distance of 100km in 2 hrs and then stops for 15 mins and covers the remaining 60km in 45 mins then find the average speed of the car.

✍Akash travels from bokaro to ranchi at the rate of 60 km per hour while returning due to bad weather the speed was 40 kms per hour .find the average speed of the total journey.

⚠️Quality answers needed⚠️
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Answer 1

Question ❶:-

• A car covers a distance of 100km in 2 hrs and then stops for 15 mins and covers the remaining 60km in 45 mins then find the average speed of the car.

Answer ❶ :-

$\sf\orange{Average \ speed⤵:-}$

$\frac{distance}{time}$

⇝Solution:-

↬Total distance = 100km + 60km = 160km

↬Total time = 2 hrs + 15 mins + 45 mins = 2 hrs + 60 mins = 3 hrs.

$\sf\purple{Total \ distance=160km:-}$

$\sf\orange{Total \ time=3hrs:-}$

↬Average speed ↧

$\frac{160km}{3hrs}$

$= 53 \ \frac{1}{3} km \: per \: hour$

$\sf\purple{The \ average \ speed \ is:-}$

➠ 53 ⅓ km/hr

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Question ❷:-

• Akash travels from bokaro to ranchi at the rate of 60 km per hour while returning due to bad weather the speed of the car was 40 kms per hour. Find the average speed of the total journey.

Answer ❷:-

➠Let the distance between the two cities be "d" km.

➠Time while going to ranchi ↧

$\frac{distance}{speed}$

$= > \: \frac{d}{60} hr$

➠Time while returning ↧

$\frac{d}{s} = > \frac{d}{40} hr$

➠Total time taken ↧

$\frac{d}{60} + \frac{d}{40}$

$\frac{2d + 3d}{120} = \frac{5d}{120} hr$

$\sf\purple{Total \ distance:-}$

→ (D + D) km

= 2 d km → Distance

$\sf\orange{Average \ speed:-}$

$\frac{distance}{time}$

$2 \: d \: km \div \frac{5d}{120} hr$

↬48km/hr

➠Hence, the average speed of the total journey is 48km/hr

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☯Additional information:-

• What is speed??

⟹ distance travelled by an object in unit time is called as speed.

• What is motion??

⟹ change in position of a body with respect to time is called as motion.

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