Question

A car covers a distance of 250
min 6 seconds. If the
acceleration of the car is
6 msFind the final velocity
2
of the car​

Answer 1

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Explanation:

do it by ur self

Answer 2

Answer:

59.66 m/s

Explanation:

Given,

distance covered(s)=250 m,

time taken,(t)=6s

acceleration,(a)=6m/s^2

let the initial velocity of the car be u and final velocity of the car be v

from the second equation of motion,

s=ut+1/2 at^2

250=u×6×1/2×6×6^2

=>u=23.66ms^1

from the first equation of motion,

v=u+at

=>v=23.66+6×6=59.66 ms^1

therefore the final velocity of the car is 59.66 ms^1