Question

A car covers a distance of 3150 in 22 hours 12 minutes. If It covers 5\7 of its journey at a speed of 150 km\h, find the speed of car for the rest of its journey

Answer 1

5/7 of its journey = 5/7 x 3150 = 2250 km

Find the time taken for the first part of the journey:

Time = Distance ÷ Speed

Time = 2250 ÷ 150 = 15 hours

Find the time taken for the second part of the journey:

22 hours 12 min - 15 hours = 7 hours 12 mins = 7.2 hours

Find the distance for the second part of the journey:

3150 - 2250 = 900 km

Find the speed of the second part of the journey:

Speed = Distance ÷ Time

Speed = 900 ÷ 7.2 = 125 km/h

Answer: The speed of the second part of the journey is 125 km/h

Answer 2

it's simple
$3150 \div 7 \times 5 = 2250$
it's means 2250km is covered by him in the speed of 150km/h ...
it's means he covered 150kmin 1h
2250km in
$1 \div 150 \times 2250 = 15h$
we have now
$22.2 - 15 = 7.2h$
$remain \: distance \: 3150 - 2250 = 900$
then remain distance will covered by him with the velocity of 900/7.2=125