A car covers a distance of 420 km at its normal speed. If the speed of the car would have been 10 km/hr more than the normal speed, then it would have taken one hour less to cover the same distance. What was the speed of the car?
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Step-by-step explanation:
Let speed of car be x km/h.
and total time in journey be 't'
then
Given x=t/420
xt=420-----(1)
and if speed =x+10
time=t-1
x+10=(t−1)420
(x+10)(t-1)=420---(2)
xt-x+10t-10=420
10t-x=430-420
10t-x=10
10t-t420=10
10t2−10t−420=0
t2−t−42=0
(t-7)(t+5)=0
t=7 & t not equal to −5
if t=7 then x=6300=90
speed of car be 90 km/h
and time journey be 7 hrs
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