Question

A car covers a distance of 720 km at a constant speed. If the speed of the car would have been 10 km/hr more, then it would have taken 1 hrs less to cover the same distance. What is the original speed of the car?

Answer 1

Answer:80km/hr

Explanation:

D1=720km D2=720km/hr

S1=X S1=X+10

Distance (D) =T×S

T=D/S

T1=720/X T2=720/X+10

T1-T2=1hr

720/X - 720/X+10 = 1

X²+10X-7200 = 0

X=80km/hr

Original speed of the car = 80km/hr.

Answer 2

Answer:

The original speed of the car is 72 km/hr.

Explanation:

Let the original speed of the car be "s" km/hr.

According to the problem, the car covers a distance of 720 km at a constant speed "s". Therefore, the time taken by the car to cover this distance is:

Time = Distance / Speed

$t_{1} =\frac{720}{s}$

If the speed of the car had been 10 km/hr more, then the time taken to cover the same distance would have been 1 hour less than t1. Therefore,

$t_{1} -1 =\frac{720}{(s+10)}$

We can simplify these two equations to get:

$\frac{720}{s} -\frac{720}{(s + 10)} = 1$

Multiplying both sides by s(s+10), we get:

720(s+10) - 720s = s(s+10)

Expanding and simplifying, we get:

7200 = 10s

Therefore, the original speed of the car is:

$s = \frac{7200}{10} = 720 km/hr$

Hence, the original speed of the car is 72 km/hr.

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