a car covers a semi circular track of radius 5m with a constant speed of π m/s find the magnitude of of displacement nd average velocity
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Displacement is the length of the shortest path between the final and initial positions which in this case, is equal to 2R = 10m.
Time taken to reach the other end of the semicircular track = Distance / Speed
= R/ Speed
=
= R = 5 s
Average velocity = Total displacement / Total time taken
= 10 / 5 = 2 m/s
Time taken to reach the other end of the semicircular track = Distance / Speed
= R/ Speed
=
= R = 5 s
Average velocity = Total displacement / Total time taken
= 10 / 5 = 2 m/s
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