Physics, asked by elukapallyj, 2 months ago


A car covers a semicircular track of radius 5 m with a constant speed of m/s. Find the magnitude of
displacement and average velocity​

Answers

Answered by abrahamchristin024
1

Answer:

Displacement = 10m  

Average velocity = 2 m/s

Explanation:

As per the provided information in the given question, we have :

A car covers a semicircular track of radius 5 m with a constant speed of π m/s.

We are asked to calculate the magnitude of displacement and average velocity.

★ Calculating displacement :

Let A to B be the length of semicircular track. We know that the displacement is defined as the shortest distance from the initial and final position. Similarly, A is here initial position and B is final position. The shortest distance will be the straight line from A to B, that is AB. AB is also here diameter of the semi-circle. So,

Therefore, displacement is 10 m.

★ Calculating average velocity :

We need to find total time first.

Since, it is a semicircular track. So, the the distance covered by the car will be the circumference divided by 2.

r = 5 [Given]

Now, we have :

Total displacement = 10 m

Total time = 5 s

Substituting values in the formula of average velocity,

Therefore, average velocity of the car is 2 m/s.

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