A car covers a semicircular track of radius 5 m with a constant speed of m/s. Find the magnitude of
displacement and average velocity
Answers
Answer:
Displacement = 10m
Average velocity = 2 m/s
Explanation:
As per the provided information in the given question, we have :
A car covers a semicircular track of radius 5 m with a constant speed of π m/s.
We are asked to calculate the magnitude of displacement and average velocity.
★ Calculating displacement :
Let A to B be the length of semicircular track. We know that the displacement is defined as the shortest distance from the initial and final position. Similarly, A is here initial position and B is final position. The shortest distance will be the straight line from A to B, that is AB. AB is also here diameter of the semi-circle. So,
Therefore, displacement is 10 m.
★ Calculating average velocity :
We need to find total time first.
Since, it is a semicircular track. So, the the distance covered by the car will be the circumference divided by 2.
r = 5 [Given]
Now, we have :
Total displacement = 10 m
Total time = 5 s
Substituting values in the formula of average velocity,
Therefore, average velocity of the car is 2 m/s.