Math, asked by shashwat3932, 1 year ago

A car covers four successive 6 km stretches at speeds of 25 kmph, 50 kmph, 75 kmph and 150 kmph respectively. Its average speed over this distance is

Answers

Answered by kratikavarshney
0
25+50+75+150+175+350=825/6=137.5

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Answered by ChitranjanMahajan
2

The average speed of the car is 50 km/hr.

• Given, a car travels a distance in four successive stretches of 6 km each, with varying speed. This means, every 6 km is travelled by the car at a different speed.

• For the first 6 km,

speed = 25 km/hr

=> Time (T1) = distance/speed = 6/25 hr

• For the second 6 km,

speed = 50 km/hr

=> Time (T2) = distance/speed = 6/50 hr

• For the third 6 km,

speed = 75 km/hr

=> Time (T3) = distance/speed = 6/75 hr

• For the fourth 6 km,

speed = 150 km/hr

=> Time (T4) = distance/speed = 6/150 hr

• Total distance travelled by the car = 6 km + 6 km + 6 km + 6 km =

24 km

Total time taken by the car to cover 24 km = T1 + T2 + T3 + T4 = 6/25 hrs + 6/50 hr + 6/75 hr + 6/150 hr

= {(6 × 6)  + (6 × 3)  + (6 × 2) + (6 × 1) } / 150 hr

= {(36 + 18 + 12 + 6) / 150 } hr

= 72/150 hr

= 12/25 hr

• Average speed = Total distance travelled / Total speed

=> Average speed of the car =

24 km / (12/25) hr = (24 × 25) / 12

= 50 km/hr

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