A car covers the first half of the distance between two places at a speed of 40 km/hr and second half at 60 km/hr the average speed of the car is:
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(1) let x/2 distance cover in time t1 & another x/2 distance cover in time t2
t1 = (x/2)/40
t2 = (x/2)/60
t1+t2 = x/48
average speed = x/(t1+t2)
= x/(x/48)
= 48Km/hr
(2) as the above
t1 = x/40
t2 = x/60
t1+t2 = x/24
average speed = 2x/(x/24)
=48Km/hr
(3) s1 = 6*2
= 12Km.
s2 = 4*3
= 12Km.
total distance = s1+s2 = 24km.
average speed = 24/5
= 4.8Km/hr
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