Question

A car covers the first half of the distance between two places at 40km/h and another half at 60km/h .The average speed of the car is what

Answer 1

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let a = average speed for the trip
let d = half the distance
:
write a time equation, time = dist/speed
d/40 + d/60 = 2d/a

we don't need d, divide thru by d and you have
1/40 + 1/60 = 2/a

multiply by 120a to clear the denominators, results:
3a + 2a = 120(2)
5a = 240
a = 240/5
a = 48 km/hr


$\boxed{Hope\:This\:Helps}$

Answer 2

Answer:

Let consider, x= total distance covered by the car,

Time taken to complete the half distance with velocity v= 40km/h,

$t_{1}$= $\frac{x}{2*40}$=$\frac{x}{80}$hr  . . . .(1)

The time taken to complete another half distance with velocity u=60km/h

$t_{2}$=$\frac{x}{2*60}$= $\frac{x}{120}$hr

The total time taken, $t_{1} +t_{2}$= t

t=$\frac{x}{80}+\frac{x}{120}$

=$\frac{x}{48}$hr

The average speed of the car,  

$v _{avg}$=$\frac{x}{x/48}$

=48 km/h

Explanation:

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