A car dealer has rupees 2500000 to invest . Each car is available for rupees 500000 . If the price of a car increases by 15%,find the number of car he can purchase for the same amount .
Answers
Answer:
4 cars
Step-by-step explanation:
Number of cars he can purchase with each car at rate 500000 = 2500000/500000 = 25/5 = 5
Price increase by 15%, so
new price = 500000 + [(15/100)×500000]
new price = 500000 + [15×5000]
new price = 500000 + 75000
new price = 575000
Number of cars he can purchase with each car at new price = 2500000/575000 = 2500/575 = 4.34
So ye can buy 4 cars in the new price as number of cars cannot be in decimal.
Kindly mark answer as brainliest, it will help :)
Step-by-step explanation:
No. of car he can purchase with each car at rate = 500000=2500000/500000=5
price increase by 15%,so
new price= 500000+(15/100)*500000
500000+75000
575000
no. of car he can purchase with new rate=
2500000/575000=4.34
he can buy 4 cars
no.of cars cannot in decimal