A car decelerates at 3 m/s2 from 68 km/h to a stop. Calculate the time for the car to come to a stop. *
Answers
Answered by
0
Answer:
Time = V- U/a => 0-68/3 => -68/3=> 22s ( Approx)
Answered by
0
according to question ; deceleration of car = -3 m/s2
: u = 68 km/h i.e 68 * 5/18 m/s and v = 0
now as we also know v = u + at
by putting values 0 = 68 x 5/18 - 3t
0 = 18.889 +3t
-18.889 = -3t
t = 6.2933
Similar questions