Physics, asked by kavinayaravichandran, 4 days ago

A car decelerates at 3 m/s2 from 68 km/h to a stop. Calculate the time for the car to come to a stop. *​

Answers

Answered by MayankSingh85
0

Answer:

Time = V- U/a => 0-68/3 => -68/3=> 22s ( Approx)

Answered by viperisbackagain
0

according to question ; deceleration of car = -3 m/s2

: u = 68 km/h i.e 68 * 5/18 m/s and v = 0

now as we also know v = u + at

by putting values 0 = 68 x 5/18 - 3t

0 = 18.889 +3t

-18.889 = -3t

t = 6.2933

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