Physics, asked by Abdul1737, 7 months ago

A car decelerates uniformly from 36 km/h to 18 km/h in 5 s. Calculate the distance traveled.

Answers

Answered by Anonymous
8

ɢɪᴠᴇɴ:

Time \: taken ,(t) = 5  \sec

Initial\:velocity ,(u) =18 km/hour

u=18×1000 ÷ 60×60s

u = 5 m/s

 Final\:velocity ,(v) =36km/hour

 v = 36×1000 ÷ 60×60s

v =10 m/s

ᴡᴇ ɴᴇᴇᴅ ᴛᴏ ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ ᴀɴᴅ ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟᴇᴅ

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ

acceleration \: (a) = (v – u)/t

sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ɢɪᴠᴇɴ ᴠᴀʟᴜᴇs ɪɴ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇϙᴜᴀᴛɪᴏɴ ᴡᴇ ɢᴇᴛ,

a = (10 – 5)/5

a =5/5

a = 1 \: m/ {s}^{2}

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟʟᴇᴅ ɪs ᴄᴀʟᴄᴜʟᴀᴛᴇᴅ ʙʏ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ

Distance \: travelled,(S) = u t + (1/2) a ×  {t}^{2}

sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ɢɪᴠᴇɴ ᴠᴀʟᴜᴇs ɪɴ ᴛʜᴇ ᴀʙᴏᴠᴇ ᴇϙᴜᴀᴛɪᴏɴ ᴡᴇ ɢᴇᴛ,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

ʜᴇɴᴄᴇ,

acceleration ,(a) =1 m/s²

Distance \: travelled ,(S) =37.5 m

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