Question

A car decrease it's speed form 8km /h to 60km/lis 5 seconds . Find the acceleration of the car​

Answer 1

Answer:

use v= u+at

Explanation:

v=60 km/hr

u=8 km/hr

t=5 s=5/3600

60=8+5/3600a

52=5/3600a

a=0.02888888....km/hr²

Answer 2

$\bold\red{AnswEr:-}$

★ Initial speed of car, u :- $80 \dfrac{km}{h}$

→ $\dfrac{8 × 1000}{3600s}$

→ $\dfrac{80}{36}ms^1$

★ Final speed of car, v :- $60 \dfrac{km}{h}$

→ $\dfrac{60 × 1000}{3600s}$

→ $\dfrac{600}{36}ms^1$

Therefore,

Acceleration, a = $\dfrac{v - u}{t}$

→ $\dfrac{ \dfrac{600}{36} - \dfrac{80}{36}}{5}$

→ $\dfrac{580}{36 × 5}$

→ $\dfrac{580}{180}$

→ $\large\bold{\underline{\boxed{\sf{\pink{3.22 ms^{-2}}}}}}$

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