Question

A car decrease its speed from 100 km/h to 80km/h in 10 seconds. find acceleration of car

Answer 1

hope it helps u........

Answer 2

Answer:

A car decreases its speed from 100 km/h to 80km/h in 10 seconds. The acceleration of the car will  be $0.55555\ m/s^2$

Explanation:

Acceleration (a) of an object is can be defined as the ratio of change in velocity and time.

then acceleration is given by,

$a = \frac{v-u}{t}$     ...(1)

where

u - the initial velocity

v - the final velocity and

t -  the time

In the question, it is given that,

$u = 100\ km/h = 100\times \frac{5}{18} = 27.7777\ m/s$

$v = 80\ km/h = 80\times \frac{5}{18} = 22.2222\ m/s$

$t = 10\ s$

Substitute these values into the equation (1)

$a = \frac{22.2222-27.7777}{10} =-0.55555\ m/s^2$

The negative acceleration is called deceleration.

The acceleration of the car = $0.55555\ m/s^2$