Question

A car decreases its speed from 80 kmh-1 to 60 kmh-1
In 5s

A. find the acceleration of the car.


B. Derive an equation for position-time relation for an in Object that traveled a distance’s’ in time 't' under uniform acceleration 'a'.

Answer 1

Answer:

t=5s

u=80km/h...that is 80×5/18m/s=22.2m/s

v=60km/h......that is 60×5/18=16.7m/s

a=v-u/t....

16.7-22.2/5

=-5.5/5

=-1.1m/s^2

Answer 2

OK dear...

Nice dαy deαr...