A car decreases its speed from 80 kmh-1 to 60 kmh-1
In 5s
A. find the acceleration of the car.
B. Derive an equation for position-time relation for an in Object that traveled a distance’s’ in time 't' under uniform acceleration 'a'.
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Answer:
t=5s
u=80km/h...that is 80×5/18m/s=22.2m/s
v=60km/h......that is 60×5/18=16.7m/s
a=v-u/t....
16.7-22.2/5
=-5.5/5
=-1.1m/s^2
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OK dear...
Nice dαy deαr...
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