A car driven at 60km/hr approaches another car going inthe se direction at 11.11m/sec if the car collides woth the second car what could ne the speed of impact?
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Solution :
Car A speed =60km/hr=60x5/18=50/3 m/s
Car B speed =42km/hr=42x5/18=35/3 m/s
Relative speed of Car A w.r.t Car B is =50/3 - 35/3=15/3=5 m/s
Total distance to be covered in overtaking = Length of both cars =10m
Time =Distance/speed=10m/5m/s=2 sec
Total distance used for overatking will be equal to distance covered by car in overtaking + length of car
=(50/3)x2+5
=100/3 +5
=33.3+5
=38.3 m
∴time taken during the overtake and the total road distance used for the overtake 38.3 m
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