a car driver driving at a speed of 90km/h applies brakes and brings the car to rest in 20s the the acceleration of the car is
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Answer:
1.25 m/s²
Explanation:
Given:
Initial velocity (u) = 90 km/h = (90 * 5/18) m/s = -25 m/s
(Since the object is decelerating, we have taken the velocity as a negative value)
Final velocity (v) = 0 m/s
Time (t) = 20 seconds
To find:
Deceleration or negative acceleration (a)
Method to find:
v = u + at
⇒ 0 = -25+ 20a
⇒ 20a = 25
⇒ a = 25/20
⇒ a = 1.25 m/s²
Hence, the deceleration of the car is 1.25 m/s².
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