A car driver driving at speed of 90 kphapplies brakes and bring the car to rast in 20s .the acceleration of the car is
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Answer:
u= 90 km/hr
=90*1000/60*60 m/sec
=25 m/sec
v= 0
t= 20 sec
using First Law of motion, v=u+at
0=90+a*20
0-90=a*20
-90/20=a
-4.5=a
acceleration is -4.5 m/sec^2
Explanation:
As, when the breaks are applied, the speed of the car decreases to zero and final velocity becomes zero. So v is taken as 0 and acceleration comes as a negative.
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