Question

A car drives 2 km west, then 8km south, and then 10 km due north. Find the car's final displacement
(magnitude and streetten)​

Answer 1

Answer:

Answer:

8 km south and 10 km north

therefore 8+10=18 Km

let  AB be 18 km

now, 2 km west

so from B to C the distance is 2km

we have to find AC

Using pythogorus theorum we can find AC

(AC)^2= (AB)^2+(BC)^2

(AC)^2= (18)^2+2^2

(AC)^2= 324+4 = 328

Explanation:

Hope it helps:)

Answer 2

Answer:

magnitude:root 8 direction:north

Explanation:

10-8=2km

2square+2square=displacement square

8=disp square

displacement=root 8