Question

a car drives by approximately
20meters from the convex side of a reflective sculpture ,and it's image appears to be one fifth the site of the car .what is the focal length of this reflective surface​

Answer 1

Answer:

hope it helps

Explanation:

b) 1/15 m/s

Focal length = f = 20 cm = 0.2 m

Distance of second car = u = -2.8m relative speed of 2nd car=v=15m/s

Relative speed of image of 2nd car=v'

m= f/(f-u) = 0.2/0.2-(-2.8) =0.2/3 = 1/ 15

v'/v = m^2

》v'/15= (1/15)^2 =1/225

》v' = 15 × 1/225 = 1/15 m/ s