Question

A car drives with a constant linear speed vi down a road with two curves. The first curve has a radius r and the second curve has radius 1/2r. How does the magnitude of the car's centripetal accelaration change after the radius decreases?

Answer 1

Answer:

32

$32 \: m \: per \: sec.........$

Answer 2

Explanation:

Hello...

The equation for the centripetal acceleration is a = v2/r. That is, acceleration is inversely proportional to the radius of the circle. If the radius is doubled, then the acceleration is halved.

Hope it's help...