Question

A car driving on a straight track accelerates at a rate of 3.2 m/s^2 for 14 sec. If the initial velocity of the car was 5.1 m/s, and its initial position was 0 m, what is its final position?

Answer 1

Explanation:

a= V-u/t

Where a=3.2m/s'2, u=5.1m/s, t=14s.

putting all the values in the above formula we get

3.2= V-5.1 /14

32*14/10= v - 5.1

44.8+5.1 = v

v = 44.8+5.1=49.9 m/s