A car falks of a leadg and dropto the ground 0.3/s let g=10m/s
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1
Given,
time taken=0.5s
g=10ms
−2
As the car is under free fall, the initial speed is zero.
(a) Under free fall,
u=0
a=g
v=u+at
v=0+10×0.5
v=5ms
−1
(b) Average speed =
2
u+v
=
2
0+5
=2.5ms
−1
(c) From newton's equation of motion, As u=0,
h=ut+
2
1
gt
2
When h is the height, t is the time of free fall, g is the acceleration due to gravity. Putting the values in the above equation, we get
h=
2
1
×10×(0.5)
2
=5×0.25=1.25m
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