Question

A car falls a ledge and drop to the ground in 2 sec. let (g=10m/s2
What is its speed in striking the ground
What is its average speed during the 2 sec?
How high is the ledge from the ground?

Answer 1

Explanation:

1. t=2s

u=0

v=u+gt

v=0+10*2

v=20m/s

2.

avg. speed=total distance/time taken

3.

h=ut+1/2gt*t

h=0*2+1/2*10*4

h=20m

Answer 2

$\huge \pink{\mathbb {Answer ツ }}$

Initial Velocity (u) = 0 m/s (as it starts from rest)

Time Taken (t) = 0.09 s

Acceleration due gravity (g) = 10 m/s²

Final Velocity (as when it streaks the ground) = ?

So, in this question we have initial Velocity, time takan & acceleration

So, we can simply get final Velocity

Formula Used :-

v = u + at

→ v = 0 + 10 × 0.9

→ v = 10 × 9/10

→ v = 1 × 9

→ v = 9

Thus, the final velocity is 9 m/s

So, the speed of car when striking the ground is 9 m/s :)

Hence done