Question

. A car falls of a ledge and drops to the ground in 0.5 s. Let g= 10 ms-2
a. What is its speed on touching the ground?
b. What is its average speed during 0.5s?
c. How high is the ledge from the ground?​

Answer 1

given

u= 0 t = o.5 s

a) v = u + gt

v = 0 + 10 *0.5

v= 5 Ms -1

( b) average speed = total distance

s = it + it 1/2 gt ^ 2

s = o*o.5 + 1/2*10 ^ 2

50 m

average speed = 50 / 0.5 = 100 Ms - 1

height = 50 m