Question

A car falls of ledge and drops to the ground in 0.6s. The value of g is 10m/s2

.

a. What is its speed on striking the ground?

b. What is its average speed during the 0.6s?

c. How high is the ledge from the ground? ​

Answer 1

Answer:

Given,

time taken=0.6s

U = 0

t = 0.5

a ) V = 0+10*0.5

V = 5 Ms - 1

b ) Average speed = total distance / total time so ,

s = ut + 1/2 gt^2

s = 0*0.5 + 1/2*10^2

s = 50m

So average speed = 50/0.5 = 100ms - 1

c ) height = 50m