Question

a car falls off a ledge and drops to the ground in 0.5 seconds at an acceleration of 10m/s square a) what is the speed on striking the ground ? b) how high is the ledge from the ground? c) what is the average speed during 0.5 seconds


pls pls pls pls pls answer thi pls requesting

Answer 1

v=u+at, here a=10m/s and t=0. 5 while it's intial velocity u is constant hence v=0+10
×0. 5=5

Answer 2

Initial velocity=0

a. Speed=u+at

v=0+10*0.5

v=5m/s

Average speed=(u+v)/2

=(0+5)/2=2.5m/s

Distance=ut+1/2at^2

=0*0.5 +1/2*10*0.5*0.5

=1.25m