Question

A car falls off a ledge and drops to the ground in 0.5 s.
Let g = 10 m s-² (for simplifying the calculation).
1) What is its speed on striking the ground?
2) what is its average speed during the 0.5 s?
3) How high is the ledge from the ground? ​

Answer 1

Answer:

time taken = 0.5 second g = 10 ms-2 As the car is under free fall, the initial speed is zero. U = 0 (a) Under free fall, u = 0, a = gv = u + a × tv = 0 + 10 × 0.5v = 5 ms-1 (b) Average speed = u+v2u+v2 = 0+520+52 = 2.5 ms-1 (c) From Newton’s equation of motion, As u=0, h = ut + 1212 gt2 Where h is the height, t is the time of free fall, g is the acceleration due to gravity. Putting the values in the above equation, we get h = 1212 x 10 x (0.5)2 = 5 x 0.25 = 1.25 mRead more on Sarthaks.com - https://www.sarthaks.com/960447/a-car-falls-off-a-ledge-and-drops-to-the-ground-in-0-5-seconds-let-g-10-ms-2-then