Question

A car falls off a ledge and drops to the ground in 0.5s. let g=10m s-2 (for simplifying the calculations).
(A) What is its speed on striking the ground?
(B) What is its average speed during the 0.5s?
(C) How high is the ledge from the ground?
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Answer 1

Answer:

ANSWER

Given,

time taken=0.5s

g=10ms

−2

As the car is under free fall, the initial speed is zero.

(a) Under free fall,

u=0

a=g

v=u+at

v=0+10×0.5

v=5ms

−1

(b) Average speed =

2

u+v

=

2

0+5

=2.5ms

−1

(c) From newton's equation of motion, As u=0,

h=ut+

2

1

gt

2

When h is the height, t is the time of free fall, g is the acceleration due to gravity. Putting the values in the above equation, we get

h=

2

1

×10×(0.5)

2

=5×0.25=1.25m

Explanation:

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