Question

A car falls off a ledge and drops to the ground in 0.5s.(Take g=10m/ssquare).Find the speed of the car on striking the ground.Find the average speed of the car in 0.5s. Find the height of the ledge from the ground.

Answer 1

$\sqrt{ \frac{2h}{g} } = t$
$\frac{2h}{10} = {0.5}^{2}$
$h = 1.25m$

therefore v = √2gh
v = √25 = 5 m/s

avg speed = total distance / total time

avg speed = 1.25/0.5 = 2.5 m/s

Answer 2

$\huge \pink{\mathbb {Answer ツ }}$

Initial Velocity (u) = 0 m/s (as it starts from rest)

Time Taken (t) = 0.09 s

Acceleration due gravity (g) = 10 m/s²

Final Velocity (as when it streaks the ground) = ?

So, in this question we have initial Velocity, time takan & acceleration

So, we can simply get final Velocity

Formula Used :-

v = u + at

→ v = 0 + 10 × 0.9

→ v = 10 × 9/10

→ v = 1 × 9

→ v = 9

Thus, the final velocity is 9 m/s

So, the speed of car when striking the ground is 9 m/s :)

Hence done