Question

A car falls off a ledge and drops to the ground in 0.6S,The value of g is 10m/s2(for simplifying the calculation
​

Answer 1

Answer:

what happened to the person who fell with the car dude... jeez get your priorities straight check what happened to the man before you measure stuff. Give him first aid or something call someone for God's Sake

Explanation:

Answer 2

$\huge \pink{\mathbb {Answer ツ }}$

Initial Velocity (u) = 0 m/s (as it starts from rest)

Time Taken (t) = 0.09 s

Acceleration due gravity (g) = 10 m/s²

Final Velocity (as when it streaks the ground) = ?

So, in this question we have initial Velocity, time takan & acceleration

So, we can simply get final Velocity

Formula Used :-

v = u + at

→ v = 0 + 10 × 0.9

→ v = 10 × 9/10

→ v = 1 × 9

→ v = 9

Thus, the final velocity is 9 m/s

So, the speed of car when striking the ground is 9 m/s :)

Hence done