Question

A car falls off a ledge and drops to the ground in 1.9 s. If the value of g is 10m/s^2 then the speed of the car on striking on the ground is

Answer 1

Answer:

8 m/s

Step-by-step explanation:

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Answer 2

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Initial Velocity (u) = 0 m/s (as it starts from rest)

Time Taken (t) = 0.09 s

Acceleration due gravity (g) = 10 m/s²

Final Velocity (as when it streaks the ground) = ?

So, in this question we have initial Velocity, time takan & acceleration

So, we can simply get final Velocity

Formula Used :-

v = u + at

→ v = 0 + 10 × 0.9

→ v = 10 × 9/10

→ v = 1 × 9

→ v = 9

Thus, the final velocity is 9 m/s

So, the speed of car when striking the ground is 9 m/s :)

Hence done