Question

A car from rest and moves along the x axis with the constant acceleration 5 ms -2 for 8 seconds

Answer 1

Answer:

u=0 a=5 m/s^2 v=? by first equation of motion v=u+at v=0+40 v=40m/s now let's find distance using 2nd equation of motion s=ut+1/2* a*t^2 ^ means square s=0+1/2*5*8^2 s=1/2*320=160 m. Hope it helps please mark my answer the brainliest and follow me.