a car get a velocity of 72km/h in 10 second. starting from rest .find 1 acceleration
2 velocity 3 distance travelled in the given time
Answers
Answered by
1
u = 0, v = 72km/hr = 20 m/s, t = 10s
from relation,
So, 20 = 0 + 10a
or, a = 2m/s2 (Ans-i)
Velocity = 20 m/s (Ans-ii)
S = 0 + 1/2 x 2x10x10
or S = 100 m (Ans-iii)
from relation,
So, 20 = 0 + 10a
or, a = 2m/s2 (Ans-i)
Velocity = 20 m/s (Ans-ii)
S = 0 + 1/2 x 2x10x10
or S = 100 m (Ans-iii)
Answered by
0
u = 0 m/s
v = 72 km/hour
= 72*(5/18)
= 20 m/s
t = 10 s
i) a = (v-u)/t
= (20-0)/10
= 20/10
= 2 m/s^2
ii) velocity = distance / time
distance = speed * time
= 20 m/s * 10 s
= 200 m
therefore , velocity = 200/10
= 20 m/s
iii)distance = speed * time
= 20 m/s * 10 s
= 200 m
v = 72 km/hour
= 72*(5/18)
= 20 m/s
t = 10 s
i) a = (v-u)/t
= (20-0)/10
= 20/10
= 2 m/s^2
ii) velocity = distance / time
distance = speed * time
= 20 m/s * 10 s
= 200 m
therefore , velocity = 200/10
= 20 m/s
iii)distance = speed * time
= 20 m/s * 10 s
= 200 m
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