Question

a car goes around a curve of radius r at a constant speed v then it goes around the same curve at half of the original speed. what is the centripetal force on the car as it goes around the curve for the second time, compared to the first time​

Answer 1

Answer:

Explanation:

a car goes around a curve of radius r at a constant speed v then it goes around the same curve at half of the original speed. the centripetal force on the car as it goes around the curve for the second time, compared to the first time​ will be

one-fourth as big

Answer 2

The new centripetal force becomes one fourth of the original force.

Explanation:

The centripetal force acting on an object moving in the circular path is given by the below formula as:

$F=\dfrac{mv^2}{r}$

Here,

m is the mass of the object

v is the speed of object

r is the radius of circular path

If the object moves in same curve at half of the original speed, v' = v/2

New centripetal force is then given by :

$F'=\dfrac{mv'^2}{r}\\\\F'=\dfrac{1}{4}\times \dfrac{mv^2}{r}\\\\F'=\dfrac{1}{4}\times F$

So, the new centripetal force becomes one fourth of the original force. Hence, this is the required solution.

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