A car goes from A to B in 3 hours. If its average speed had been 9 km/h an hour slower, it would have taken4 hours. Find the distance of B from A.
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first we have to find the distance of A =D= s*t so ,9*3 so we will find 27km the distance from A to B now we will find the distance from B toA so according to the question s=9, t=4, then d= s*t=4*9=36 km is the distance from B to A the car is 9 km late
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