A car goes from a town A to another town B with a speed of 40km/h and returns back to town A with a speed of 60km/h.The average speed of the car during the complete journey is?Please mention the process please
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Answered by
360
Speed taken to go town A to town B=40 km/hr
Speed of car from going station B to A=60 km/hr.
Let the distance be x km.
Then the time will be distance /speed.
For A to B, Time taken=x/40.(t 1)
For B to A, Time taken=x/60.(t 2)
Total time =t 1 + t 2
=>x/40 + x/60 =( 3x + 2x)/120
-> 5x/120 = x/24
Average speed = Total distance / Total time
2x/x/24 =48 km /hr.
ANSWER = 48 km /hr.
Speed of car from going station B to A=60 km/hr.
Let the distance be x km.
Then the time will be distance /speed.
For A to B, Time taken=x/40.(t 1)
For B to A, Time taken=x/60.(t 2)
Total time =t 1 + t 2
=>x/40 + x/60 =( 3x + 2x)/120
-> 5x/120 = x/24
Average speed = Total distance / Total time
2x/x/24 =48 km /hr.
ANSWER = 48 km /hr.
samaira1112:
This is the right answer
Answered by
66
Answer:
48km/hr
Explanation:
Average Speed is 48 Kmph
Lets take the distance between the station A & B is 120 Km.
Speed for travelling from station A to B is 40 Kmph so it takes 3 Hrs to reach.
Speed for travelling from station B to A is 60 Kmph so it takes 2 Hrs to return.
Now,
Total distance travelled is 240 Km
Total travelling time is 5 Hrs
Average speed =total Distance travelled / total time taken
= 240/5
= 48 Km/Hr
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