A
car goes from
a town A to another
town B with a speed of 40 km/h and
return back to the town. A with a
speed of 60 km/h. The average speed
of the car
during the compelete
journey is :
Answers
Answer:
Speed taken to go town A to town B=40 km/hr
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2=>x/40 + x/60 =( 3x + 2x)/120
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2=>x/40 + x/60 =( 3x + 2x)/120-> 5x/120 = x/24
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2=>x/40 + x/60 =( 3x + 2x)/120-> 5x/120 = x/24Average speed = Total distance / Total time
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2=>x/40 + x/60 =( 3x + 2x)/120-> 5x/120 = x/24Average speed = Total distance / Total time2x/x/24 =48 km /hr.
Speed taken to go town A to town B=40 km/hrSpeed of car from going station B to A=60 km/hr.Let the distance be x km.Then the time will be distance /speed.For A to B, Time taken=x/40.(t 1)For B to A, Time taken=x/60.(t 2)Total time =t 1 + t 2=>x/40 + x/60 =( 3x + 2x)/120-> 5x/120 = x/24Average speed = Total distance / Total time2x/x/24 =48 km /hr.ANSWER = 48 km /hr.
Step-by-step explanation:
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