Question

a car goes on horizontal road of radius 4m, the speed of car is increasing at a constant rate of 3m/se, the friction coefficient between road and tyre is 0.5, the speed at which the car will skid,is​

Answer 1

Answer:

If the speed of the body is increasing in

case of the circular motion. This means

that the magnitude of the Velocity is

changing at the Constant rate.

This also tell that there is a tangential

acceleration which is produced due to

the change in magnitude of the velocity.

.: tangential acceleration = dv/dt = a

Now, Centripetal Acceleration = v/r

(222 + a2

.: Net Acceleration =

.: m * accele.(net) =

my()2 + a2

→ There will be Frictional Force which

will balances the Force produced due to

the tangential acceleration.

.: umg=m/(5)2 + a2

→ u?g2 = v^/r2 + a2

→ v4/r2 = u?g?-a?

.: V = [r2(ug2-02)