A car goes straight from a point to a point b with a velocity of 40km/hr and returns back with a velocity of 60km/hr.The average velocity during the whole journey is
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The average velocity =2/(1/40+1/60)
=(2*40*60)/(40+60)=48km/hr
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Let the distance between a and b is x
so,, time taken from a to be = 40/x
and time taken from b to a = 60/x
so, total time of journey= 40/x +60/x
average velocity=total displacement/total time
average velocity= 0/tatal time =0 {because car would be back at its initial point}
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