Question

A car going 15 m/s is brought to rest in a distance of 2.0 m as it strikes a pile of dirt. Ho w large an average force is exerted by seatbelts on a 90 kg passenger as the car is stopp ed?

Answer 1

Answer:

5062.5N

Explanation:

u=15m/s

v=0m/s

s=2m

m=90kg

a=?

v²=u²+2as

0=225+2(a)(2)

a=-225/4

f=ma=90×(-225/4)=-10125/2=-5062.5N

force by belt is equal to 5062.5N

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