A car going 15 m/s is brought to rest in a distance of 2.0 m as it strikes a pile of dirt. Ho w large an average force is exerted by seatbelts on a 90 kg passenger as the car is stopp ed?
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Answer:
5062.5N
Explanation:
u=15m/s
v=0m/s
s=2m
m=90kg
a=?
v²=u²+2as
0=225+2(a)(2)
a=-225/4
f=ma=90×(-225/4)=-10125/2=-5062.5N
force by belt is equal to 5062.5N
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