Question

A car has 1500 kg its velocity reduced from 20 meter per second to 15 meter per second during 30 seconds. How large is the retarding force?​

Answer 1

Explanation:

A 1500 kg car has its velocity reduced from 20 meter per second to 15 meter per second during 30 seconds. How large is the retarding force?

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We know that the velocity of the car dropped from 20 m/s to 15 m/s over a course of 30 seconds.

We know that acceleration is given by (v-u)/t. Substituting v=15, u=20 and t = 30, gives an acceleration of -0.16667 m/s^2 (a negative acceleration means a deceleration).

We know that force = mass x acceleration. We know that m = 1500 and that a = -0.16667, so the force is 1500 x (-0.16667) = -250 N.

Since a retarding force is always in the negative direction, the retarding force is 250 newtons.

Answer 2

Answer:

mass=1500kg

v=20m/s

u=15m/s

t=30sec.

so for acceleration, 20-15/30=0.166m/s^2

then for force =mass multiply by acceleration,

1500*0.166=249N