Question

A car has a uniform acceleration of 4m s2 what distance will it cover in 10th that second order is start​

Answer 1

Given:

• Acceleration of the car = 4 m/s²
• Initial velocity = 0 m/s
• Time taken = 10s

To find:

• Distance covered at 10th second

Solution:

Using the third kinematic equation of motion .

s = ut + 1/2 at²

Where

• s → distance = ?
• u → initial velocity = 0 m/s
• a → acceleration = 4 m/s²
• t → time taken = 10s

Here , initial velocity will be 0m/s because the car starts from rest.

Substituting the known values we have

→ s = 0(10) + 1/2 × 4(10)²

→ s = 0 + 2(10)²

→ s = 0 + 2 × 100

→ Distance travelled = 200m

Hence , distance travelled = 200 m