Question

A car has a uniform acceleration of 8m/s2.The distance cover by it in 10s after start is -

(a) 200m

(b) 400m

(c) 600m

(d) 800m

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Answer 1

YOUR ANSWER IS :

• 600cm

i hope this will help you....

Answer 2

Given :-

Acceleration = 8 m/s²

Time taken = 10 s

To Find :-

The distance cover by it in 10 s after start.

Analysis :-

$\sf s=ut+\dfrac{1}{2} \: at^{2}$

Solution :-

We know that,

• u = Initial velocity
• t = Time
• a = Acceleration
• s = Displacement

We know that,

Acceleration = 8 m/s²

Time taken = 10 s

By the third equation of motion,

$\underline{\boxed{\sf s=ut+\dfrac{1}{2} \: at^{2}}}$

Here initial velocity u = 0 since the car starts from rest

Substituting their values, we get

$\sf s=0 \times t+\dfrac{1}{2} \times 8 \times 100$

$\sf s=400 \ m$

Therefore, distance traveled by car is 400 m