Question

A car has a velocity of 10m/s. it accelerates at 0.2m/s for half minute. find the distance travelled during this time and the final velocity of the car

Answer 1

Solution :

⏭ Given:

✏ Initial velocityof car = 10m/s

✏ Acceleration = 0.2$\sf{ms^[-2}}$

✏ Time interval = 1/2min

⏭ To Find:

1. Distance
2. Final velocity

⏭ Conversation:

✏ 1/2min = 30s

⏭ Calculation:

• Distance :

$\mapsto \sf \: d = ut + \dfrac{1}{2} a {t}^{2} \\ \\ \mapsto \sf \: d =( 10 \times 30) + (0.5 \times 0.2 \times 900) \\ \\ \mapsto \sf \: d = 300 + 90 \\ \\ \mapsto \boxed{ \sf{ \red{d =390 \: m }}} \: \star$

• Final velocity :

$\mapsto \sf \: v = u + at \\ \\ \mapsto \sf \: v = 10 + (0.2 \times 30) \\ \\ \mapsto \sf \: v = 10 + 6 \\ \\ \mapsto \: \boxed{ \sf{ \blue{v = 16 \: mps}}} \: \star$

Answer 2

Given :

Initial velocity (u) = 10 m/s

Acceleration (a) = 0.2 m/s²

Time = 1/2 minute = 30 seconds

To find :

1) Distance travelled (s)

2) Final velocity (v)

Solution :

1) By using second equation of motion :

=> $s = ut + \dfrac{1}{2} a {t}^{2}$

=> $s =( 10 \times 30) + \dfrac{1}{2} \times 0.2 \times {(30)}^{2}$

=> $s = 300 + 0.1 \times 900$

=> s = 300 + 90

=> s = 390 m

2) By using first equation of motion :

=> v = u + at

=> v = 10 + 0.2 × 30

=> v = 10 + 6

=> v = 16 m/s

Answer :

Distance travelled = 390 m

Final velocity = 16 m/s