Question

a car has a velocity of 10ms-1 .it accelerates at 0.2ms-2 for half minute .find the distance travelled during this time and the final velocity of the car

Answer 1

Answer:

the distance travelled during this time  390 m

the final velocity of the car 16 ms-1

Explanation:

u=10ms-1

t=0.5 min=30sec

a=0.2ms-2

S=ut+0.5at*t

 =10*30+0.5*0.2*30*30

 =390 m

and

v = u+at

  = 10 + 0.2*30

  = 16 ms-1