Question

A car has a velocity of 10ms-1. it accelerates at 0.2ms2 for half minute. find the distance travelled during this time and the final velocity of car

Answer 1

Explanation:

Given:-

• Initial velocity (u) = 10m/s

• Acceleration (a) = 0.2m/s²

• Time (t) = ½ minute

To Find:-

• The distance traveled by the car.

• The final velocity of the car.

Solution:-

u = 10m/s , a = 0.2m/s²

Time (t) = ½ minute = 30 sec

Final velocity (v) = ?

Distance (s) = ?

Using 1st equation of motion:-

$\sf \implies v = u + at$

$\sf \implies v = 10 + (0.2 \times 30)$

$\sf \implies v = 10 + 6$

$\sf \implies v = 16m/s$

$\sf \therefore \underline{\:\: \underline{\: Final \: velocity = 16m/s\:}\:\:}$

Using 3rd equation of motion:-

$\sf \implies s = ut + \dfrac{1}{2}at^2$

$\sf \implies s = (10 \times 30) + \dfrac{1}{2} \times 0.2 \times {(30)}^{2}$

$\sf \implies s = (300) + (0.1 \times 900)$

$\sf \implies s = 300+ 90$

$\sf \implies s = 390$

$\sf \therefore \underline{\:\: \underline{\: Distance \: travelled = 390m\:}\:\:}$

Answer 2

Given:

✰ Initial velocity of car ( u ) = 10m/s

✰ Acceleration ( a ) = 0.2 m/s²

✰ Time ( t ) = 1/2 minutes = 30 sec

Conversion:

Time ( t ) = 1/2 minutes

Now convert these minutes into seconds.

By using simple unitary method:

1 minute = 60 sec

1/2 minutes = 1/2 × 60

= 30 sec

To find:

❀ Distance travelled by car.

❀ Final velocity of car.

Solution:

➢ Initial velocity of car ( u ) = 10m/s

➢ Acceleration ( a ) = 0.2 m/s²

➢ Time ( t ) = 1/2 minutes = 30 sec

➢ Distance travelled by car ( S ) = ?

➢ Final velocity of car ( v ) = ?

Applying, S = ut + 1/2 at²

Here, we are using second equation of motion.

➯ S = ut + 1/2 at²

➯ S = ( 10 × 30 ) + 1/2 × 0.2 × ( 30 )²

➯ S = 300 + 1/2 × 0.2 × 900

➯ S = 300 + 0.1 × 900

➯ S = 300 + 90

➯ S = 390 m

∴ Distance travelled by car ( S ) = 390 m

Now,

Applying, v = u + at

Here, we have used first equation of motion.

➯ v = u + at

➯ v = 10 + ( 0.2 × 30 )

➯ v = 10 + 6

➯ v = 16 m/s

∴ Final velocity of car ( v ) = 16 ms^-1

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