Question

a car has a velocity of 15m\s. it then accelerates at a uniform rate of 3.5m\s2 for the next 5.0-sec wat distance does the car cover during this time

Answer 1

Answer:

Correct option is

B

8.10 m s

−2

using second eq of motion s=ut+1/2at

2

as u=0, a=

t

2

2s

=

5.21

2

2∗110

=8.10m/s

2

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Answer 2

Answer:

we know,

s=ut+1/2at 2

s=(15*50+1/2*4*50*50)m

s=(750+5000)m

s=5750m

therefore distance traveled is5750 meters